2[3(x-2)-1]+1=8x-11

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Solution for 2[3(x-2)-1]+1=8x-11 equation: 


Simplifying
2[3(x + -2) + -1] + 1 = 8x + -11

Reorder the terms:
2[3(-2 + x) + -1] + 1 = 8x + -11
2[(-2 * 3 + x * 3) + -1] + 1 = 8x + -11
2[(-6 + 3x) + -1] + 1 = 8x + -11

Reorder the terms:
2[-6 + -1 + 3x] + 1 = 8x + -11

Combine like terms: -6 + -1 = -7
2[-7 + 3x] + 1 = 8x + -11
[-7 * 2 + 3x * 2] + 1 = 8x + -11
[-14 + 6x] + 1 = 8x + -11

Reorder the terms:
-14 + 1 + 6x = 8x + -11

Combine like terms: -14 + 1 = -13
-13 + 6x = 8x + -11

Reorder the terms:
-13 + 6x = -11 + 8x

Solving
-13 + 6x = -11 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
-13 + 6x + -8x = -11 + 8x + -8x

Combine like terms: 6x + -8x = -2x
-13 + -2x = -11 + 8x + -8x

Combine like terms: 8x + -8x = 0
-13 + -2x = -11 + 0
-13 + -2x = -11

Add '13' to each side of the equation.
-13 + 13 + -2x = -11 + 13

Combine like terms: -13 + 13 = 0
0 + -2x = -11 + 13
-2x = -11 + 13

Combine like terms: -11 + 13 = 2
-2x = 2

Divide each side by '-2'.
x = -1

Simplifying
x = -1

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